How to get the value of a file field in PHP

2 years ago
William Carter
1 minute

To obtain the value of a file field, you can use the $_FILES superglobal variable. The specific steps are as follows:

  1. Add a name attribute to the file field in an HTML form, for example.
  2. In PHP scripts, use the $_FILES superglobal variable to access the value of the file field. $_FILES is an array that contains information about all the file fields in the form.
  3. Retrieve the original file name of the uploaded file using $_FILES[‘fileField’][‘name’].
  4. Use $_FILES[‘fileField’][‘tmp_name’] to obtain the temporary file name of the uploaded file.

Below is a simple example code:

<form action="upload.php" method="post" enctype="multipart/form-data">
    <input type="file" name="fileField">
    <input type="submit" value="Upload">
</form>

<?php
if ($_SERVER['REQUEST_METHOD'] === 'POST') {
    // 获取上传文件的原始文件名
    $fileName = $_FILES['fileField']['name'];

    // 获取上传文件的临时文件名
    $tmpFileName = $_FILES['fileField']['tmp_name'];

    // 其他操作，例如将文件保存到指定目录中
    move_uploaded_file($tmpFileName, 'uploads/' . $fileName);
}
?>

In the example above, we obtained the original file name of the uploaded file using $_FILES[‘fileField’][‘name’] and the temporary file name using $_FILES[‘fileField’][‘tmp_name’]. Next, we can use the move_uploaded_file function to save the uploaded file to a specified directory.

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