What is the concept and purpose of the pointer in cout in C++?

In C++, cout is a standard output stream object used to print text to the console. If you use cout to output a pointer, it will print the memory address that the pointer is pointing to rather than the value of the pointer.

A pointer is a variable that stores a memory address. Therefore, using cout to output a pointer can help us debug and understand the behavior of the pointer. It can be used to verify if the pointer is pointing to the expected memory location, or to output the specific data that the pointer is pointing to.

Here is an example showing how to use cout to output a pointer:

int main() {
    int num = 10;
    int* ptr = #

    std::cout << "指针的值: " << ptr << std::endl; // 输出指针的值，即内存地址
    std::cout << "指针所指向的值: " << *ptr << std::endl; // 输出指针所指向的值，即num的值

    return 0;
}

The output will be similar to:

指针的值: 0x7ffeedd6f7fc
指针所指向的值: 10

By examining the value of the pointer and the value it points to, we can understand the behavior of the pointer and debug our program.