How to read images using PHP file_get_contents?

To use the file_get_contents function to read an image, you need to provide the URL address of the image as a parameter. Here is an example code:

$imageUrl = 'https://example.com/image.jpg';
$imageData = file_get_contents($imageUrl);

// 保存图片到本地文件
file_put_contents('path/to/save/image.jpg', $imageData);

In the above example, $imageUrl is the URL address of the image, and $imageData is the image content retrieved using the file_get_contents function. You can then use the file_put_contents function to save the image content to a local file. Please replace “path/to/save/image.jpg” with the local path where you want to save the image.

Please note that using file_get_contents to read large or remote images from a server may result in memory overflow. In such cases, consider using the stream_context_create function and fopen function to handle it. Here is an example of using stream_context_create and fopen functions:

$imageUrl = 'https://example.com/image.jpg';

$context = stream_context_create(['http' => ['user_agent' => 'Mozilla/5.0 (Windows NT 6.1; rv:35.0) Gecko/20100101 Firefox/35.0']]);
$imageFile = fopen('path/to/save/image.jpg', 'w');
stream_copy_to_stream(fopen($imageUrl, 'r', false, $context), $imageFile);
fclose($imageFile);

In the above example, the stream_context_create function is used to create a context containing user agent information to avoid restrictions on access by certain remote servers. Then, the fopen function is used to open local and remote image files, and the stream_copy_to_stream function is used to copy the content of the remote image to the local file. Finally, close the file handle. Also, please replace path/to/save/image.jpg with the local path where you want to save the image.

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