How to obtain the generics implemented in an interface in Java?

In Java, you can obtain the implementation of a generic interface by using the following method:

1. MyInterface interface that takes a generic type T
2. Could you put that in your own words in English?

Code example:

interface MyInterface<T> {
    void method(T t);
}

class MyClass implements MyInterface<String> {
    @Override
    public void method(String s) {
        System.out.println(s);
    }
}

public class Main {
    public static void main(String[] args) {
        MyInterface<?> obj = new MyClass();
        obj.method("Hello");
    }
}

1. Specify the generic type explicitly when implementing an interface: When implementing an interface, you can specify the specific type of the generic explicitly.

Example code:

interface MyInterface<T> {
    void method(T t);
}

class MyClass implements MyInterface<String> {
    @Override
    public void method(String s) {
        System.out.println(s);
    }
}

public class Main {
    public static void main(String[] args) {
        MyInterface<String> obj = new MyClass();
        obj.method("Hello");
    }
}

Both methods can be used to obtain the generic type of the implemented interface. The choice of method depends on your specific requirements and code structure.