How do you pass C language arrays to parameters?

In the C language, arrays can be passed to a function parameter in two ways:

1. Passing a pointer to an array: When passing an array, what is actually passed is the starting address of the array. The formal parameter can be declared as a pointer to the data type of the array. Inside the function, you can access the elements of the array using the pointer.

The sample code is as follows:

#include <stdio.h>

void printArray(int arr[], int size) {
    for (int i = 0; i < size; i++) {
        printf("%d ", arr[i]);
    }
    printf("\n");
}

int main() {
    int arr[] = {1, 2, 3, 4, 5};
    int size = sizeof(arr) / sizeof(arr[0]);

    printArray(arr, size);

    return 0;
}

The output is: 1 2 3 4 5

1. Passing the array’s pointer and its length as parameters: In addition to passing the array’s pointer, you can also pass the array’s length as a parameter. This way, you can access the array’s elements within the function and know the length of the array.

The sample code is as follows:

#include <stdio.h>

void printArray(int *arr, int size) {
    for (int i = 0; i < size; i++) {
        printf("%d ", arr[i]);
    }
    printf("\n");
}

int main() {
    int arr[] = {1, 2, 3, 4, 5};
    int size = sizeof(arr) / sizeof(arr[0]);

    printArray(arr, size);

    return 0;
}

The output remains the same: 1 2 3 4 5

Both methods can achieve passing arrays, the choice between the two depends on specific requirements and programming habits.