How can files in a folder be parsed using the Perl language?

One option could be:
In Perl language, you can use the File::Find module to parse files in a folder. Here is a simple example:

use strict;
use warnings;
use File::Find;

# 定义一个用于处理文件的回调函数
sub process_file {
    my $file = $_;
    # 在这里对文件进行处理,比如输出文件路径
    print "File: $File::Find::name\n";
}

# 定义要解析的文件夹路径
my $dir = '/path/to/directory';

# 调用File::Find模块的find函数,传入回调函数和文件夹路径
find(\&process_file, $dir);

In the above code, the `find` function of the `File::Find` module is used to apply the `process_file` callback function to every file in the specified folder. In the `process_file` function, any processing of the file can be done, such as outputting the file path.

Please note that you need to install the File::Find module first, you can use CPAN or a package management tool to install it.

bannerAds