How to implement executing a method when starting up Dj…

In Django, you can use the ready() method of the AppConfig class to execute a certain method when Django starts.

Firstly, in the apps.py file of your application, create a subclass inheriting from the AppConfig class and override the ready() method. For example, if your application is named myapp, you can create a MyAppConfig class.

from django.apps import AppConfig

class MyAppConfig(AppConfig):
    name = 'myapp'

    def ready(self):
        # 在这里编写你要执行的方法
        my_method()

Next, in the __init__.py file of your application, set the default_app_config variable to the path of the MyAppConfig class (e.g. myapp.apps.MyAppConfig):

default_app_config = 'myapp.apps.MyAppConfig'

Finally, write the method you want to execute in your application at any location. For example:

def my_method():
    # 这里是你要执行的方法的代码
    pass

When Django starts up, the ready() method is automatically called, executing the methods you have written.

Please note that the execution time of the ready() method is after Django has been initialized, but before all applications have finished executing their ready() methods. Therefore, you can safely use various Django features and models inside the ready() method.