What is the method for storing a string in reverse orde…

One way to reverse store a string using pointers is as follows:

1. Firstly, declare a new character pointer variable to store the reversed string.
2. You can use the library function strlen() to calculate the length of the original string.
3. Allocate memory dynamically for a new pointer variable in order to store the reversed string. The malloc() library function can be used.
4. Copy each character from the original string starting from the last one to a new pointer string using a loop.
5. After the loop ends, set the last character of the new pointer string to the end symbol ‘\0’.
6. Finally, you can use the new pointer string for further operations, such as printing or saving.

The following is an example code:

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

int main() {
    char *str = "Hello World";
    int length = strlen(str);
    char *reversed_str = (char*) malloc((length + 1) * sizeof(char)); // 分配内存

    for (int i = length - 1; i >= 0; i--) {
        reversed_str[length - i - 1] = str[i]; // 逆序复制字符
    }
    reversed_str[length] = '\0'; // 添加结束符

    printf("Reversed String: %s\n", reversed_str);

    free(reversed_str); // 释放内存

    return 0;
}

The code above will output: Reversed String: Hello World